Physics word problem. Help?
Mar
10
10
y = y0 + v0*t + 1/2*a*t^2 where y is position, y0 is initial position, v0 is initial velocity, t is time, and a is acceleration
Lets call the top of the shaft y = 0. This means that y0 = 0 and depth you are looking for y = -79 m . v0 is also zero, since the rock starts at rest. Since up is the positive direction, acceleration is negative (gravity). Plug in and solve.
#If you have any other info about this subject , Please add it free.# |
Posted in enart.mercebank.com by rose| edit
